Find out the original Normality of a Secondary standard substrates solution

Find out the original Normality of a Secondary standard substrates   solution

Primary standard substrates are Na₂CO₃(Lab grade), Oxalic Acid(Lab grade) etc.

Secondary standard substrates are HCl , NaOH etc.

We can find out the original normality of  Secondary standard substrates by compare with the  Primary standard substrates.

Process : Make 1 N Na₂CO₃ solution.(5.3 mg in 100 ml water in V.F)

                  Make 1 N HCl Solution.(3.65 mg in 100 ml water in V.F)

Stapes:

1.      Keep 10 ml Na₂CO₃ solution in conical flax.

2.      Than add P.I in conical flax.

3.      Borate will be fill by HCl solution.

4.      Than titration will be start.

5.      After complete the titration read the borate HCL solution volume. Exa : 11 ml.

Formula : S₁V₁=S₂V₂                       (Na₂CO₃ =HCl)

                  1*10=S₂*11

                   S₂=10/11 = 0.90N     (The actual normality of HCl solution is 0.90N ).

Now we found out the actual normality of NaOH By Standard HCl 0.90 N solution.

                Make 1 N NaOH solution.

Stapes:

1.      Keep 10 ml NaOH solution in conical flax.

2.      Than add P.I in conical flax.

3.      Borate will be fill by HCl solution.

4.      Than titration will be start.

5.      After complete the titration read the borate HCL solution volume. Exa : 10.9 ml.

Formula : S₁V₁=S₂V₂                      (HCl=NaOH)

                  0.90*10.9=S₂*10

                   S₂=9.81/10 = 0.98N  (The actual normality of Na₂CO₃solution is 0.90N ).

Formula for Normality:

37% HCL     – Special gravity 1litter     = 1.19 kg (Grade of sample 37)

98%H₂SO₄   – Special gravity 1 litter    = 1.84 kg (Grade of sample 98)

(N.B:37% means 37% HCL gas present on this solution same for  98%H₂SO₄  )

Find out normality for LAB HCL / H₂SO₄ :

Make necessary normality solution(For Liquid):

S₁V₁=S₂V₂                                                        Here: S₁ = Normality of lad HCL/H₂SO₄

V₁ = S₂V₂/ S₁                                                            S₂ = Necessary normality of HCL/H₂SO₄

                                                                                    V₁ = Necessary amount of  HCL/H₂SO₄

                                                                                    V₂ = Amount/Volume of Solution. 

Such as :                                                                    

100 ml 1 N HCl Solution                                          

V₁ = 1*100/12 =8.33 ml (HCl)

For solid:

Such as:

 100 ml 1 N solution (NaOH) = 40/1000 * 100   (gm) = 4 mg (NaOH)

100 ml  1 N Solution (KMnO₄)  = 158/1000 * 100 (mg) =15.8 gm(KMnO₄)  / 1.58 mg (KMnO₄) for making 0.1 N solution